(1×2+1×3+⋯9×10)×2(1×2+1×3+⋯9×10) × 2 (1×2+1×3+⋯9×10)×2 =(1+2+3+⋯+9+10)2−(12+22+32+⋯+92+102)= (1+2+3+⋯+9+10)^2 −(1^ 2 +2^2 +3^2 +⋯+9^2 +10^2 )=(1+2+3+⋯+9+10)2−(12+22+32+⋯+92+102)
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dora2012
SU
@ 2025-6-17 13:18:29